Friday, 25 January 2013

COMPUTER KNOWLEDGE

161. What is the shortcut key to select all in MS-Excel?
(a) Ctrl + S
(b) Ctrl + A
(c) Alt + A
(d) Alt + S


162. ________ is not a storage medium.
(a) CD
(b) DVD
(c) Hard disk
(d) Monitor


163. Which part of the Computer performs arithmetical calculations?
(a) Monitor
(b) Memory
(c) ALU
(d) CPU


164. OCR stands for:
(a) Optical Character Recognition
(b) Original Coding Recognizer
(c) Original Character Reader
(d) Optional Coding Recognizer


165. What is the first step in the transaction cycle?
(a) Data transfer
(b) Data entry
(c) Audit
(d) None of these



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166. What is Output?
(a) Processor takes from the user
(b) The user gives to the processor
(c) The processor gets from the user
(d) The processor gives to the user


167. Help menu is available at button
(a) Start
(b) Turf off
(c) End
(d) Restart


168. Short cut Key to open a new database is
(a) Ctrl+ N
(b) Ctrl + S
(c) Ctrl + Z
(d) Ctrl + V


169. Short cut Key to open an existing database is
(a) Ctrl+ N
(b) Ctrl + O
(c) Ctrl + Z
(d) Ctrl + V


170. Short Cut Key to quit Microsoft Access
(a) Alt + F5
(b) Alt + F4
(c) Alt + F2
(d) Alt + F1


171. A pixel is a
(a) Picture element or dot on a screen.
(b) Point of ink on a laser printed page.
(c) Point of ink on an ink jet-printed page.
(d) None of these


172. Which is the correct format to save the web pages?
(a) html://
(b) http://
(c) HTML
(d) URL


173. ‘WWW stands for:
(a) World Wide Web
(b) World Work Web
(c) Work Wide Web
(d) Work White Web


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174. How we can measure the display size of a monitor
(a) Diagonally
(b) Vertically
(c) Horizontally
(d) None of these


175. LCD stands for:
(a) Liquid Crystal Display
(b) Legal Crystal Display
(c) Liquid Computer Display
(d) Local Crystal Display


176. Which algorithm is used for data integrity?
(a) SED
(b) AES
(c) MD5
(d) None of these


177. Which is not a form of Biometrics?
(a) Fingerprint
(b) Retina scan
(c) Password
(d) None of these


178. _____ is called the permanent memory in computer.
(a) DVD
(b) RAM
(c) ROM
(d) CPU


179. What type of device is a 31/2 inch floppy drive?
(a) Input
(b) Output
(c) Software
(d) Storage
(e) None of these


180. Each cell in a Microsoft Office Excel documents is referred to by its cell address, which is
the:
(a) Cell’s column label and worksheet tab name
(b) Cell’s column label
(c) Cell’s row label
(d) Cell’s row and column labels
(e) Cell’s contents


181. The access method used for magnetic tape is .
(a) Sequential
(b) Direct
(c) None of the above
(d) Random
(e) All

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182. The difference between memory and storage is that the memory is and storage is
(a) Permanent, temporary
(b) Slow, fast
(c) Temporary, permanent
(d) None of the above
(e) All


183. Which of the following devices can be used to directly input printed text
(a) OMR
(b) OCR
(c) MICR
(d) None of the above
(e) All


184. A floppy disk contains
(a) Sector Only
(b) Both circular tracks and sectors
(c) Circular tracks only
(d) None of the above
(e) All


185. CD-ROM is a
(a) Memory register
(b) Semiconductor memory
(c) Magnetic memory
(d) None of the above
(e) All


186. Which of the following is used as a primary storage device
(a) PROM
(b) Magnetic tape
(c) Floppy disk
(d) None of the above
(e) All


187. Operating system is
(a) A collection of input-output devices
(b) A collection of software routines
(c) A collection of hardware components
(d) None of the above
(e) All


188. Operating system
(a) Provides a layered, user-friendly interface
(b) Link a program with subroutines it references
(c) Enables a programmer to draw a flowchart
(d) None of the above
(e) All


189. Modem stands for
(a) Modulator demodulator
(b) Mainframe operating device memory
(c) A type of secondary memory
(d) None of the above
(e) All

                                                                   
                                                               
190. Wide area networks (WANs) always require
(a) High speed processors
(b) Same type
(c) High bandwidth communication source link
(d) None of the above
(e) All


191. Bug means
(a) A difficult syntax error in a program
(b) A logical error in a program
(c) Documenting programs using an efficient documentation too
(d) None of the above
(e) All


192. C is-
(a) A low level language
(b) A third generation high level language
(c) A machine language
(d) None of the above
(e) An assembly language


193. The communication line between the CPU, memory and peripherals is called a
(a) Bus
(b) Media
(c) Wire
(d) Line
(e) None of these


194. One thousand bytes represent a
(a) Terabyte
(b) Kilobyte
(c) Gigabyte
(d) Megabyte
(e) None of the above


195. A step by step procedure used to solve a problem is called
(a) Software
(b) Algorithm
(c) Operating system
(d) Application system
(e) None of the above


196. The errors that cannot be pointed out by the compiler are
(a) Syntax errors
(b) Bug
(c) Semantic errors
(d) Logical errors


197. WAN hardware includes
(a) EDF
(b) FTP
(c) Multiplexors and routers
(d) None of the above
(e) Bridger and modems


198. The central Processing Unit:
(a) Is operated from the control panel.
(b) Controls the auxiliary storage unit
(c) Is controlled by the input data entering the system
(d) None of these
(e) Controls all input, output and processing


199. Which of the following is not hardware:
(a) Magnetic tape
(b) VDU terminal
(c) Assembler
(d) None of these
(e) Printer


200. Pick out the wrong definition:
(a) Control unit-heart of a computer.
(b) COBOL-a language used for business data processing
(c) Access time-time needed to access the output
(d) None of these
(e) EDP-acronym for Electronic Data Processing
H.C.F. & L.C.M. OF NUMBERS
 
If a number x divides another number y exactly, then x is said to be a factor of y. To add, subtract, or just compare two fractions, we need to convert both fractions to a common denominator. The least common multiple is usually used, although any common multiple would work in this particular case. Here comes the concept of Least Common Multiple (L.C.M.). Also to simplify a fraction, we divide the numerator and the denominator by the same number. If we divide them by the greatest common factor, then no further simplifications are required. That greatest common factor is called the Highest Common Factor (H.C.F.) or Greatest Common Divisor (G.C.D.). Least Common Multiple (L.C.M.): The least number which is exactly divisible by each one of the given numbers is called their L.C.M. There are two methods of finding the L.C.M .of two or more than two numbers:
1. Factorization Method: In this method first resolve each one of the given numbers into a product of Prime factors. Then Least Common Multiple is the product of highest powers of all the factors.
2. Common Division Method: In this method first arrange the set of numbers in any order. Then take a number which divides exactly at least two of the given numbers and carry forward the remaining numbers which are not divisible by that particular number. Repeat the process till no two of the numbers are divisible by the same number. Then Least Common Factor is the product of the divisors and the undivided numbers.
Highest Common Factor (H.C.F.): The H.C.F. of two or more than two numbers is the greatest number that divides each of them exactly. There are two methods of finding the H.C.F. of two or more than two numbers: Factorization Method: First resolve each one of the given numbers as the product prime factors. Then H.C.F. is the product of least powers of common prime factors. Division Method: If we want to find out the H.C.F. of two numbers then divide the larger number by smaller one. Again divide the divisor by the remainder. We should repeat this process till zero is obtained as remainder. If we have three numbers then H.C.F. of {(H.C.F. of any two) and (the third number)} will be the H.C.F. of three given numbers. Important Formulas of L.C.M. and H.C.F. of Numbers – Product of two numbers =Product of their H.C.F and L.C.M.
1. H.C.F. = H.C.F.of NumeratorsL.C.M.of Denominators
2. L.C.M. = L.C.M.of NumeratorsH.C.F.of Denominators
Solved Examples 

Example 1. Find the L.C.M. of 50, 35 and 70. Solution. Let us apply the Factorization Method to find the L.C.M. of 50, 35 and 70. Express each one of the given number as the product of prime factors.
50 = 2 × 52, 35 = 5 × 7, 70 = 2 × 5 × 7. ∴L.C.M. = Product of highest powers of 2, 5 and 7 = 2 × 52 × 7 = 350. 

Example 2. Find the L.C.M. of 18, 20, 24, and 54. Solution. Let us apply Common Division Method to find the L.C.M. of 18, 20, 24, 54.

Directions: Mark the correct Answer:
1. Find the highest common factor of 54 and 36.
(a) 4
(b) 6
(c) 16
(d) 18


2. Find the lowest common multiple of 24, 20 and 30.
(a) 120
(b) 50
(c) 64
(d) 24


3. The H.C.F. of 25 , 169 , 1825 is:
(a) 4225
(b) 2225
(c) 24125
(d) 2125


4. The L.C.M. of 23 , 1627 , 512 is:
(a) 803
(b) 809
(c) 695
(d) 495


5. The ratio of two numbers is 3:4 and their H.C.F. is 4.Their L.C.M. is:
(a) 12
(b) 16
(c) 24
(d) 48


6. The L.C.M. of two numbers is 189 and H.C.F. of two numbers is 9. If one of the number is 63 then other number is:
(a) 27
(b) 28
(c) 29
(d) 30


7. The H.C.F. of 3.6, 7.2, 2.1, 0.81 is:
(a) 0.3
(b) 0.03
(c) 0.9
(d) 0.09


8. The L.C.M. of 1.8, 3.6, and 0.72 is:
(a) 3.6
(b) 11.8
(c) 0.36
(d) 10.80


9. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case
(a) 4
(b) 7
(c) 9
(d) 13


10. Three different containers contain 204 litres, 1190 litres and 1445 litres of Pepsi, Slice and Coca-Cola respectively. What biggest measure can be measured from all the different quantities of cold drinks exactly?
(a) 17
(b) 18
(c) 19
(d) 20


Answers
1. (d)
2. (a)
3. (b)
4. (a)
5. (d)
6. (a)
7. (b)
8. (d)
9. (a)
10. (a)
Solution and Explanation
1. 54 = 2×3×3×3, 36 = 3 ×2×3×2,
Therefore, H.C.F. = 2×3×3 =18.
2. 24 = 2×2 ×2×3, 20 = 2×2 ×5 , 30= 2×3×5.
Therefore, L.C.M. = products of highest powers of 2, 3 and 5 = 23 × 3 × 5 =120.
8. L.C.M. of 180, 360,72 =1080.
Therefore, L.C.M. of 1.8, 3.6, and 0.72 is 10.80
9. Required number will be = H.C.F. of (91 -43), (183 -91) and (183 – 43) = H.C.F. of 48, 92, 140 =4

ONLINE EXAM NUMERICAL ABILITY


NUMERICAL ABILITY
 

SIMPLIFICATION

Some Important Concepts ‘BODMAS’ Rule: This ‘BODMAS’ Rule shows the correct sequence of all the operations that are to be executed to find out the value of a given expression. In this rule ‘B’ Stands for ‘Bracket’, ‘O’ stands for ‘of’, ‘D’ for ‘Division’, ‘M’ for ‘Multiplication’, ‘A’ for ‘Addition’ and ‘S’ for ‘Subtraction’. Therefore, the correct order to simplify an expression is:
(a) ( )
(b) {}
(c) []
(d) of
(e) Division
(f) Multiplication
(g) Addition
(h) Subtraction


Exercise
1. (-2) (-4) (5) ( 110 ) = ?
(a) 4
(b) -4
(c) 2
(d) 1
2. 7÷ 77 × 77077 =?
(a) 707
(b) 777
(c) 7007
(d) 7707
3. If 56 – [12 – {2+4 – (2+?)}] = 45.What should come at the place of ‘?’ in the equation.
(a) 3
(b) 4
(c) 5
(d) 6
4. 5? = 107
(a) 2/7
(b) 3/7
(c) 7/3
(d) 7/2
5. Evaluate: 9−2−[ 4−(1+1) ]÷2|6−2|−|3−6 |÷3.
(a) 2
(b) 3
(c) 4
(d) 5
6. How many 14s are there in 49 12 .
(a) 195
(b) 196
(c) 197
(d) 198
7. The smallest number which should be subtracted from the sum of 115, 213, and 316 to make the result a whole number is:
(a) 0.5
(b) 0.8
(c) 0.7
(d) 0.9
8. If x * y = 𝑥𝑥2 + y, then what is the value of p in the expression (2 * 4) * p = 100?
(a) 36
(b) 74
(c) 65
(d) 76
9. 5 is added to a certain number; the sum is multiplied by 3; the product is divided by 4 and 2 is subtracted from the quotient. The remainder left is 4. What will be the number?
(a) 4
(b) 5

(c) 2
(d) 3
10. 0.004 × 0.02 × 0.8 ÷ (0.2 × 0.40) =?
(a) 0.8
(b) 0.08
(c) 0.008
(d) 0.0008
11. The value of 13+13+ 13−13 is:
(a) 2689
(b) 2789
(c) 2889
(d)2589
12. Which of the following values of m and n satisfy the equation I and II.
I. 2m + 4n = 8 II. 8m + 6n = 22
(a) 1,2
(b) 2,1
(c) 1,1
(d) 2,2
13. How many pieces of 25 cm length can be cut from a 62.5 meters long Aluminum stick?
(a) 500
(b) 230
(c) 240
(d) 225
14. If one fourth of a tank holds 45 liters of milk, then the quantity of water that one third of the tank holds is:
(a) 65L
(b) 60L
(c) 62L
(d) 61L
15. A cricket team won 3 matches more than they lost. If a win gives them 2 points and loss (-1) point, how many matches, in all, have they played if their score is 23.
(a) 34 matches
(b) 35 matches
(c) 36 matches
(d) 37 matches


Answers
1. (a)
2. (c)
3. (a)
4. (d)
5. (a)
6. (d)
7. (c)
8. (a)
9. (d)
10. (d)
11. (b)
12. (a)
13. (d)
14. (b)
15. (d)



Solution and Explanation
1. Given expression is (2 × 4 × 5 ×110) = 4.
2. 7÷ 77 × 77077 =7707711= 7007
3. 56 – [12 – {2+4 – (2+?)}] = 45 ⇔ 56 – [12 – 4 –?] = 45⇔? = 3.
4. 5? = 107 ⇔? = 5 × 710⇔ ? = 72.
5. Given Expression: 9−2−[ 4−(1+1) ]÷2|6−2|−|3−6 |÷3= 7−[ 4−2 ]÷2|4|−|−3 |÷3= = 7−2÷24−3÷3= 7−14−1 = 63 = 2.
6. Required number: 49 1214 = 992 × 41 = 198.
7. Sum of all the fractions = 115 + 213 + 316 = 20130 = 6.7. The whole number just less than 6.7 is 6, then the required number = 6.7- a = 6 a = 0.7.
8. Given expression: (2 * 4) * p = 100 ⇔(4 + 4) * p = 100 ⇔64 + p = 100 ⇔p =36.
9. Suppose the required number is x then,
3 ( x+5)4 – 2 = 4 ⇔ 3(x + 5) – 8 = 16⇔x + 5 = 24/3 ⇔x = 3.
10. 0.004 × 0.02 × 0.8 0.2 × 0.40 = 648 ×10000 = 0.0008.
11. Given expression: 13+13+ 13−13 = 13+13+ 183 = 13+13+ 38 = 13+1 278 = 13+8 27 = 13+8 27 = 189 27 = 2789
12. I. 2m + 4n = 8 II.8m + 6n =22.
Multiplying (I) by 4 and subtract the (II) from (I), then we get n =1. Put n=1 in (I) then we get m=2.
13. Number of pieces = 62.5 ×10025 = 625025 = 250.
14. Suppose the capacity of the tank is x litres. Then, 14 x = 45 ⇔x = 180 ⇔13 x = 60.
15. Suppose they have lost x matches. Then, number of matches won = x+3.
∴ 2(x+3) – x = 23 ⇔x =17. Hence, total number of matches played by the team = x + (x+3) = 2x + 3 =37.

Monday, 21 January 2013

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