ONLINE EXAM NUMERICAL ABILITY

NUMERICAL ABILITY 

SIMPLIFICATION

Some Important Concepts ‘BODMAS’ Rule: This ‘BODMAS’ Rule shows the correct sequence of all the operations that are to be executed to find out the value of a given expression. In this rule ‘B’ Stands for ‘Bracket’, ‘O’ stands for ‘of’, ‘D’ for ‘Division’, ‘M’ for ‘Multiplication’, ‘A’ for ‘Addition’ and ‘S’ for ‘Subtraction’. Therefore, the correct order to simplify an expression is:
(a) ( )
(b) {}
(c) []
(d) of
(e) Division
(f) Multiplication
(g) Addition
(h) Subtraction


Exercise
1. (-2) (-4) (5) ( 110 ) = ?
(a) 4
(b) -4
(c) 2
(d) 1
2. 7÷ 77 × 77077 =?
(a) 707
(b) 777
(c) 7007
(d) 7707
3. If 56 – [12 – {2+4 – (2+?)}] = 45.What should come at the place of ‘?’ in the equation.
(a) 3
(b) 4
(c) 5
(d) 6
4. 5? = 107
(a) 2/7
(b) 3/7
(c) 7/3
(d) 7/2
5. Evaluate: 9−2−[ 4−(1+1) ]÷2|6−2|−|3−6 |÷3.
(a) 2
(b) 3
(c) 4
(d) 5
6. How many 14s are there in 49 12 .
(a) 195
(b) 196
(c) 197
(d) 198
7. The smallest number which should be subtracted from the sum of 115, 213, and 316 to make the result a whole number is:
(a) 0.5
(b) 0.8
(c) 0.7
(d) 0.9
8. If x * y = 𝑥𝑥2 + y, then what is the value of p in the expression (2 * 4) * p = 100?
(a) 36
(b) 74
(c) 65
(d) 76
9. 5 is added to a certain number; the sum is multiplied by 3; the product is divided by 4 and 2 is subtracted from the quotient. The remainder left is 4. What will be the number?
(a) 4
(b) 5
(c) 2
(d) 3
10. 0.004 × 0.02 × 0.8 ÷ (0.2 × 0.40) =?
(a) 0.8
(b) 0.08
(c) 0.008
(d) 0.0008
11. The value of 13+13+ 13−13 is:
(a) 2689
(b) 2789
(c) 2889
(d)2589
12. Which of the following values of m and n satisfy the equation I and II.
I. 2m + 4n = 8 II. 8m + 6n = 22
(a) 1,2
(b) 2,1
(c) 1,1
(d) 2,2
13. How many pieces of 25 cm length can be cut from a 62.5 meters long Aluminum stick?
(a) 500
(b) 230
(c) 240
(d) 225
14. If one fourth of a tank holds 45 liters of milk, then the quantity of water that one third of the tank holds is:
(a) 65L
(b) 60L
(c) 62L
(d) 61L
15. A cricket team won 3 matches more than they lost. If a win gives them 2 points and loss (-1) point, how many matches, in all, have they played if their score is 23.
(a) 34 matches
(b) 35 matches
(c) 36 matches
(d) 37 matches

Answers
1. (a)
2. (c)
3. (a)
4. (d)
5. (a)
6. (d)
7. (c)
8. (a)
9. (d)
10. (d)
11. (b)
12. (a)
13. (d)
14. (b)
15. (d)


Solution and Explanation
1. Given expression is (2 × 4 × 5 ×110) = 4.
2. 7÷ 77 × 77077 =7707711= 7007
3. 56 – [12 – {2+4 – (2+?)}] = 45 ⇔ 56 – [12 – 4 –?] = 45⇔? = 3.
4. 5? = 107 ⇔? = 5 × 710⇔ ? = 72.
5. Given Expression: 9−2−[ 4−(1+1) ]÷2|6−2|−|3−6 |÷3= 7−[ 4−2 ]÷2|4|−|−3 |÷3= = 7−2÷24−3÷3= 7−14−1 = 63 = 2.
6. Required number: 49 1214 = 992 × 41 = 198.
7. Sum of all the fractions = 115 + 213 + 316 = 20130 = 6.7. The whole number just less than 6.7 is 6, then the required number = 6.7- a = 6 a = 0.7.
8. Given expression: (2 * 4) * p = 100 ⇔(4 + 4) * p = 100 ⇔64 + p = 100 ⇔p =36.
9. Suppose the required number is x then,
3 ( x+5)4 – 2 = 4 ⇔ 3(x + 5) – 8 = 16⇔x + 5 = 24/3 ⇔x = 3.
10. 0.004 × 0.02 × 0.8 0.2 × 0.40 = 648 ×10000 = 0.0008.
11. Given expression: 13+13+ 13−13 = 13+13+ 183 = 13+13+ 38 = 13+1 278 = 13+8 27 = 13+8 27 = 189 27 = 2789
12. I. 2m + 4n = 8 II.8m + 6n =22.
Multiplying (I) by 4 and subtract the (II) from (I), then we get n =1. Put n=1 in (I) then we get m=2.
13. Number of pieces = 62.5 ×10025 = 625025 = 250.
14. Suppose the capacity of the tank is x litres. Then, 14 x = 45 ⇔x = 180 ⇔13 x = 60.
15. Suppose they have lost x matches. Then, number of matches won = x+3.
∴ 2(x+3) – x = 23 ⇔x =17. Hence, total number of matches played by the team = x + (x+3) = 2x + 3 =37.